For the reaction \[PC{{l}_{5}}(g)\]⇌ \[PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] [MP PET 1996]

\[{{K}_{p}}={{K}_{c}}{{(RT)}^{2}}\]

\[{{K}_{p}}={{K}_{c}}{{(RT)}^{-1}}\]

For the reaction \[PC{{l}_{5}}(g)\]⇌ \[PC{{l}_{3}}(g)+C{{l}_{2}}(g)\

1.	For the reaction \[PC{{l}_{5}}(g)\]⇌ \[PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] [MP PET 1996]
A.	\[{{K}_{p}}={{K}_{c}}\]
B.	\[{{K}_{p}}={{K}_{c}}{{(RT)}^{-1}}\]
C.	\[{{K}_{p}}={{K}_{c}}(RT)\]
D.	\[{{K}_{p}}={{K}_{c}}{{(RT)}^{2}}\]
Answer» D. \[{{K}_{p}}={{K}_{c}}{{(RT)}^{2}}\]

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For the reaction \[PC{{l}_{5}}(g)\]⇌ \[PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] [MP PET 1996]

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