For the reaction \[N{{H}_{4}}HS(g)\rightleftharpoons N{{H}_{3}}(g)+{{H}_{2}}S(g)\] in a closed flask, the equilibrium pressure is P atm. The standard free energy of the reaction would be:

For the reaction \[N{{H}_{4}}HS(g)\rightleftharpoons N{{H}_{3}}(g)+{{H

1.	For the reaction \[N{{H}_{4}}HS(g)\rightleftharpoons N{{H}_{3}}(g)+{{H}_{2}}S(g)\] in a closed flask, the equilibrium pressure is P atm. The standard free energy of the reaction would be:
A.	\[-RT\] ln p
B.	\[-RT\] (ln p - ln 2)
C.	\[-2RT\] ln p
D.	\[-2RT\] (ln p - ln 2)
Answer» E.

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For the reaction \[N{{H}_{4}}HS(g)\rightleftharpoons N{{H}_{3}}(g)+{{H}_{2}}S(g)\] in a closed flask, the equilibrium pressure is P atm. The standard free energy of the reaction would be:

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