For the reaction \[{{N}_{2(g)}}+3{{H}_{2(g)}}\] ⇌ \[2N{{H}_{3(g)}}\], the correct expression of equilibrium constant K is [CPMT 1984, 2000]

\[K=\frac{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}{{{[N{{H}_{3}}]}^{2}}}\]

\[K=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}\]

\[K=\frac{2[N{{H}_{3}}]}{[{{N}_{2}}]\times 3[{{H}_{2}}]}\]

\[K=\frac{[{{N}_{2}}]\times 3[{{H}_{2}}]}{2[N{{H}_{3}}]}\]

For the reaction \[{{N}_{2(g)}}+3{{H}_{2(g)}}\] ⇌ \[2N{{H}_{3(g)}}\]

1.	For the reaction \[{{N}_{2(g)}}+3{{H}_{2(g)}}\] ⇌ \[2N{{H}_{3(g)}}\], the correct expression of equilibrium constant K is [CPMT 1984, 2000]
A.	\[K=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}\]
B.	\[K=\frac{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}{{{[N{{H}_{3}}]}^{2}}}\]
C.	\[K=\frac{2[N{{H}_{3}}]}{[{{N}_{2}}]\times 3[{{H}_{2}}]}\]
D.	\[K=\frac{[{{N}_{2}}]\times 3[{{H}_{2}}]}{2[N{{H}_{3}}]}\]
Answer» B. \[K=\frac{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}{{{[N{{H}_{3}}]}^{2}}}\]

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For the reaction \[{{N}_{2(g)}}+3{{H}_{2(g)}}\] ⇌ \[2N{{H}_{3(g)}}\], the correct expression of equilibrium constant K is [CPMT 1984, 2000]

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