For the reaction : \[{{H}_{2(g)}}+C{{O}_{2(g)}}\] ⇌\[C{{O}_{(g)}}+{{H}_{2}}{{O}_{(g)}}\], if the initial concentration of \[[{{H}_{2}}]=[C{{O}_{2}}]\] and \[x\] moles/litre of hydrogen is consumed at equilibrium, the correct expression of \[{{K}_{p}}\] is [Orissa JEE 2005]

\[\frac{{{(1+x)}^{2}}}{{{(1-x)}^{2}}}\]

\[\frac{{{x}^{2}}}{{{(1-x)}^{2}}}\]

\[\frac{{{x}^{2}}}{{{(2+x)}^{2}}}\]

\[\frac{{{x}^{2}}}{1-{{x}^{2}}}\]

For the reaction : \[{{H}_{2(g)}}+C{{O}_{2(g)}}\] ⇌\[C{{O}_{(g)}}+

1.	For the reaction : \[{{H}_{2(g)}}+C{{O}_{2(g)}}\] ⇌\[C{{O}_{(g)}}+{{H}_{2}}{{O}_{(g)}}\], if the initial concentration of \[[{{H}_{2}}]=[C{{O}_{2}}]\] and \[x\] moles/litre of hydrogen is consumed at equilibrium, the correct expression of \[{{K}_{p}}\] is [Orissa JEE 2005]
A.	\[\frac{{{x}^{2}}}{{{(1-x)}^{2}}}\]
B.	\[\frac{{{(1+x)}^{2}}}{{{(1-x)}^{2}}}\]
C.	\[\frac{{{x}^{2}}}{{{(2+x)}^{2}}}\]
D.	\[\frac{{{x}^{2}}}{1-{{x}^{2}}}\]
Answer» B. \[\frac{{{(1+x)}^{2}}}{{{(1-x)}^{2}}}\]

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For the reaction : \[{{H}_{2(g)}}+C{{O}_{2(g)}}\] ⇌\[C{{O}_{(g)}}+{{H}_{2}}{{O}_{(g)}}\], if the initial concentration of \[[{{H}_{2}}]=[C{{O}_{2}}]\] and \[x\] moles/litre of hydrogen is consumed at equilibrium, the correct expression of \[{{K}_{p}}\] is [Orissa JEE 2005]

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