1.

For the reaction, \[3A+2B\to C+D\], the differential rate law can be written as:

A. \[\frac{1}{3}\frac{d[A]}{dt}=\frac{d[C]}{dt}=k{{[A]}^{n}}{{[B]}^{m}}\]
B. \[-\frac{d[A]}{dt}=\frac{d[C]}{dt}=k{{[A]}^{n}}{{[B]}^{m}}\]
C. \[+\frac{1}{3}\frac{d[A]}{dt}=-\frac{d[C]}{dt}=k{{[A]}^{n}}{{[B]}^{m}}\]
D. \[-\frac{1}{3}\frac{d[A]}{dt}=\frac{d[C]}{dt}=k{{[A]}^{n}}{{[B]}^{m}}\]
Answer» E.


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