1.

For the given orthogonal matrix Q,\(Q = \left[ {\begin{array}{*{20}{c}} {\frac{3}{7}}&{\frac{2}{7}}&{\frac{6}{7}}\\ { - \frac{6}{7}}&{\frac{3}{7}}&{\frac{2}{7}}\\ {\frac{2}{7}}&{\frac{6}{7}}&{ - \frac{3}{7}} \end{array}} \right]\)The inverse is __________

A. \(\left[ {\begin{array}{*{20}{c}} {\frac{3}{7}}&{\frac{2}{7}}&{\frac{6}{7}}\\ { - \frac{6}{7}}&{\frac{3}{7}}&{\frac{2}{7}}\\ {\frac{2}{7}}&{\frac{6}{7}}&{ - \frac{3}{7}\;} \end{array}} \right]\)
B. \(\left[ {\begin{array}{*{20}{c}} { - \frac{3}{7}}&{ - \frac{2}{7}}&{ - \frac{6}{7}}\\ {\frac{6}{7}}&{ - \frac{3}{7}}&{ - \frac{2}{7}}\\ { - \frac{2}{7}}&{ - \frac{6}{7}}&{\frac{3}{7}} \end{array}} \right]\)
C. \(\left[ {\begin{array}{*{20}{c}} {\frac{3}{7}}&{ - \frac{6}{7}}&{\frac{2}{7}}\\ {\frac{2}{7}}&{\frac{3}{7}}&{\frac{6}{7}}\\ {\frac{6}{7}}&{\frac{2}{7}}&{ - \frac{3}{7}} \end{array}} \right]\)
D. \(\left[ {\begin{array}{*{20}{c}} { - \frac{3}{7}}&{\frac{6}{7}}&{ - \frac{2}{7}}\\ { - \frac{2}{7}}&{ - \frac{3}{7}}&{ - \frac{6}{7}}\\ { - \frac{6}{7}}&{ - \frac{2}{7}}&{\frac{3}{7}} \end{array}} \right]\)
Answer» D. \(\left[ {\begin{array}{*{20}{c}} { - \frac{3}{7}}&{\frac{6}{7}}&{ - \frac{2}{7}}\\ { - \frac{2}{7}}&{ - \frac{3}{7}}&{ - \frac{6}{7}}\\ { - \frac{6}{7}}&{ - \frac{2}{7}}&{\frac{3}{7}} \end{array}} \right]\)


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