For the electrochemical cell, \[M|{{M}^{+}}||{{X}^{-}}|X,\]\[{{E}^{o}}({{M}^{+}}/M)\] = 0.44 V and \[{{E}^{o}}(X/{{X}^{-}})\]= 0.33 V. From this data one can deduce that [IIT-JEE (Screening) 2000]

\[M\,+\,X\,\to {{M}^{+}}+{{X}^{-}}\] is the spontaneous reaction

\[{{M}^{+}}+{{X}^{-}}\to M+X\] is the spontaneous reaction

For the electrochemical cell, \[M|{{M}^{+}}||{{X}^{-}}|X,\]\[{{E}^{o}}

1.	For the electrochemical cell, \[M\|{{M}^{+}}\|\|{{X}^{-}}\|X,\]\[{{E}^{o}}({{M}^{+}}/M)\] = 0.44 V and \[{{E}^{o}}(X/{{X}^{-}})\]= 0.33 V. From this data one can deduce that [IIT-JEE (Screening) 2000]
A.	\[M\,+\,X\,\to {{M}^{+}}+{{X}^{-}}\] is the spontaneous reaction
B.	\[{{M}^{+}}+{{X}^{-}}\to M+X\] is the spontaneous reaction
C.	\[{{E}_{cell}}\]= 0.77 V
D.	\[{{E}_{cell}}\]= ? 0.77 V
Answer» C. \[{{E}_{cell}}\]= 0.77 V

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For the electrochemical cell, \[M|{{M}^{+}}||{{X}^{-}}|X,\]\[{{E}^{o}}({{M}^{+}}/M)\] = 0.44 V and \[{{E}^{o}}(X/{{X}^{-}})\]= 0.33 V. From this data one can deduce that [IIT-JEE (Screening) 2000]

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