MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
| 1. |
For a uniformly loaded rectangular area, the Newmark’s influence factor given by ___________ |
| A. | \(K= \left[\frac{20.20.4\sqrt{(0.2^2+0.4^2+1)}}{0.2^2+0.4^2+0.2^2 0.4^2+1}*\frac{0.2^2+0.4^2+2}{0.2^2+0.4^2+1}+tan^{-1}\frac{20.20.4\sqrt{(0.2^2+0.4^2+1)}}{0.2^2+0.4^2+0.2^2 0.4^2+1}\right] \) |
| B. | \(K= \frac{1}{4π} \left[\frac{20.20.4\sqrt{(0.2^2+0.4^2+1)}}{0.2^2+0.4^2+0.2^2 0.4^2+1}*\frac{0.2^2+0.4^2+2}{0.2^2+0.4^2+1}+tan^{-1}\frac{20.20.4\sqrt{(0.2^2+0.4^2+1)}}{0.2^2+0.4^2+0.2^2 0.4^2+1}\right] \) |
| C. | \(K= \frac{1}{4π}\) |
| D. | \(K= \frac{q}{4π} \left[\frac{20.20.4\sqrt{(0.2^2+0.4^2+1)}}{0.2^2+0.4^2+0.2^2 0.4^2+1}*\frac{0.2^2+0.4^2+2}{0.2^2+0.4^2+1}+tan^{-1}\frac{20.20.4\sqrt{(0.2^2+0.4^2+1)}}{0.2^2+0.4^2+0.2^2 0.4^2+1}\right] \) |
| Answer» C. \(K= \frac{1}{4π}\) | |