MCQOPTIONS
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| 1. |
For a gaseous reaction: \[2{{A}_{2}}(g)+5{{B}_{2}}(g)\to 2{{A}_{2}}{{B}_{5}}(g)\] at \[{{27}^{o}}C\] the heat change at constant pressure is found to be \[-\,50160\,J\]. Calculate the value of internal energy change \[(\Delta E)\]. Given that R = 8.314 J/K mol. |
| A. | - 34689 J |
| B. | - 37689 J |
| C. | - 27689 J |
| D. | - 38689 J |
| Answer» C. - 27689 J | |