MCQOPTIONS
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| 1. |
For a continuous series the mode is computed by the formula |
| A. | \[l+\frac{{{f}_{m-1}}}{{{f}_{m}}-{{f}_{m-1}}-{{f}_{m+1}}}\times C\] or \[l+\left( \frac{{{f}_{1}}}{{{f}_{m}}-{{f}_{1}}-{{f}_{2}}} \right)\times i\] |
| B. | \[l=\frac{{{f}_{m}}-{{f}_{m-1}}}{{{f}_{m}}-{{f}_{m-1}}-{{f}_{m+1}}}\times C\] or \[l+\frac{{{f}_{m}}-{{f}_{1}}}{{{f}_{m}}-{{f}_{1}}-{{f}_{2}}}\times i\] |
| C. | \[l+\frac{{{f}_{m}}-{{f}_{m-1}}}{2{{f}_{m}}-{{f}_{m-1}}-{{f}_{m+1}}}\times C\] or \[l+\frac{{{f}_{m}}-{{f}_{1}}}{2{{f}_{m}}-{{f}_{1}}-{{f}_{2}}}\times i\] |
| D. | \[l+\frac{2{{f}_{m}}-{{f}_{m-1}}}{{{f}_{m}}-{{f}_{m-1}}-{{f}_{m+1}}}\times C\] or \[l+\frac{2{{f}_{m}}-{{f}_{1}}}{{{f}_{m}}-{{f}_{1}}-{{f}_{2}}}\times i\] |
| Answer» D. \[l+\frac{2{{f}_{m}}-{{f}_{m-1}}}{{{f}_{m}}-{{f}_{m-1}}-{{f}_{m+1}}}\times C\] or \[l+\frac{2{{f}_{m}}-{{f}_{1}}}{{{f}_{m}}-{{f}_{1}}-{{f}_{2}}}\times i\] | |