Fluorine is more electronegative than either boron or phosphorus. What conclusion can be drawn from the fact that \[B{{F}_{3}}\] has no dipole moment but \[P{{F}_{3}}\] does [Pb. PMT 1998]

\[B{{F}_{3}}\]is not spherically symmetrical but \[P{{F}_{3}}\] is

\[B{{F}_{3}}\]molecule must be linear

The atomic radius of \[P\] is larger than the atomic radius of \[B\]

The \[B{{F}_{3}}\] molecule must be planar triangular

Fluorine is more electronegative than either boron or phosphorus. What

1.	Fluorine is more electronegative than either boron or phosphorus. What conclusion can be drawn from the fact that \[B{{F}_{3}}\] has no dipole moment but \[P{{F}_{3}}\] does [Pb. PMT 1998]
A.	\[B{{F}_{3}}\]is not spherically symmetrical but \[P{{F}_{3}}\] is
B.	\[B{{F}_{3}}\]molecule must be linear
C.	The atomic radius of \[P\] is larger than the atomic radius of \[B\]
D.	The \[B{{F}_{3}}\] molecule must be planar triangular
Answer» E.

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Fluorine is more electronegative than either boron or phosphorus. What conclusion can be drawn from the fact that \[B{{F}_{3}}\] has no dipole moment but \[P{{F}_{3}}\] does [Pb. PMT 1998]

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