Find the Taylor Series expansion of sinh (x) centered around 5?

Question

TuteeHUB · Accepted Answer

$\frac{(x-5)}{1!}+\frac{(x-5)^3}{3!}+\frac{(x-5)^5}{5!}+…\infty$

TuteeHUB · Answer

$\frac{x}{1!}+\frac{x^3}{3!}+\frac{x^5}{5!}+…..\infty$

TuteeHUB · Answer

$\frac{(x-5)}{1!}+\frac{(x-5)^3}{3!}+\frac{(x-5)^5}{5!}+…\infty$

TuteeHUB · Answer

$1+\frac{x^2}{2!}+\frac{x^4}{4!}+…\infty$

TuteeHUB · Answer

$-(\frac{(x-5)}{1!}+\frac{(x-5)^3}{3!}+\frac{(x-5)^5}{5!}+…\infty)$

1.	Find the Taylor Series expansion of sinh (x) centered around 5?
A.	\(\frac{x}{1!}+\frac{x^3}{3!}+\frac{x^5}{5!}+…..\infty\)
B.	\(\frac{(x-5)}{1!}+\frac{(x-5)^3}{3!}+\frac{(x-5)^5}{5!}+…\infty\)
C.	\(1+\frac{x^2}{2!}+\frac{x^4}{4!}+…\infty\)
D.	\(-(\frac{(x-5)}{1!}+\frac{(x-5)^3}{3!}+\frac{(x-5)^5}{5!}+…\infty)\)
Answer» B. \(\frac{(x-5)}{1!}+\frac{(x-5)^3}{3!}+\frac{(x-5)^5}{5!}+…\infty\)

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