1.

Find the sum to n terms of the series whose nth term is n (n-2).

A. \(\frac{n(n-1)(2n+4)}{6}\)
B. \(\frac{n(n+1)(2n-5)}{6}\)
C. \(\frac{(n-2)(2n-5)}{3}\)
D. \(\frac{n(n+1)(2n-5)}{3}\)
Answer» C.


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