1.

Find the L(sin3 t).

A. \(\frac{3}{4(s^2+1)}-\frac{1}{4(s^2+9)}\)
B. \(\frac{3}{4(s^2+1)}-\frac{3}{4(s^2+9)}\)
C. \(\frac{3}{4(s^2+1)}-\frac{9}{4(s^2+9)}\)
D. \(\frac{3}{4(s^2-1)}-\frac{3}{4(s^2+9)}\)
Answer» C. \(\frac{3}{4(s^2+1)}-\frac{9}{4(s^2+9)}\)


Discussion

No Comment Found