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1. |
Find relation between a and b such that the following limit is got after a single application of L hospitals Rule (lt_{x rightarrow 0} frac{ae^x+be^{2x}}{be^x+ae^{2x}} ) |
A. | <sup>b</sup> <sub>a</sub> = 2 |
B. | <sup>a</sup> <sub>b</sub> = 2 |
C. | a = b |
D. | a = -b |
Answer» E. | |