1.

Find relation between a and b such that the following limit is got after a single application of L hospitals Rule (lt_{x rightarrow 0} frac{ae^x+be^{2x}}{be^x+ae^{2x}} )

A. <sup>b</sup> <sub>a</sub> = 2
B. <sup>a</sup> <sub>b</sub> = 2
C. a = b
D. a = -b
Answer» E.


Discussion

No Comment Found