MCQOPTIONS
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| 1. |
Find nth derivative of x2y2 + xy1 + y = 0 |
| A. | x<sup>2</sup>y<sub>n+2</sub> + (2n+1)xy<sub>n+1</sub> + (n<sup>2</sup>+1)y<sub>n</sub> = 0 |
| B. | x<sup>2</sup>y<sub>n+2</sub> + nxy<sub>n+1</sub> + (n<sup>2</sup>+1)y<sub>n</sub> = 0 |
| C. | x<sup>2</sup>y<sub>n+2</sub> + (2n+1)xy<sub>n+1</sub> + n<sup>2</sup>y<sub>n</sub> = 0 |
| D. | x<sup>2</sup>y<sub>n+2</sub> + 2nxy<sub>n+1</sub> + n<sup>2</sup>y<sub>n</sub> = 0 |
| Answer» B. x<sup>2</sup>y<sub>n+2</sub> + nxy<sub>n+1</sub> + (n<sup>2</sup>+1)y<sub>n</sub> = 0 | |