_FeO (s) + CO (g) = Fe (s) + CO‚Äö√á√á (g), k = 0. 435 at 1173E; At equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173 K?$?

_FeO (s) + CO (g) = Fe (s) + CO‚Äö√á√á (g), k = 0. 435 at 11

1.	_FeO (s) + CO (g) = Fe (s) + CO‚Äö√á√á (g), k = 0. 435 at 1173E; At equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173 K?$?
A.	1.0
B.	1.3
C.	2.3
D.	3.3
Answer» E.