\[f(x)=\frac{\log (\pi +x)}{\log (e+x)}\] is

1.	\[f(x)=\frac{\log (\pi +x)}{\log (e+x)}\] is
A.	Increasing in \[[0,\infty )\]
B.	Decreasing in \[[0,\infty )\]
C.	Decreasing in \[\left[ 0,\frac{\pi }{e} \right]\] & increasing in \[\left[ \frac{\pi }{e},\infty \right]\]
D.	Increasing in \[\left[ 0,\frac{\pi }{e} \right]\] & decreasing in \[\left[ \frac{\pi }{e},\infty \right)\]
Answer» C. Decreasing in \[\left[ 0,\frac{\pi }{e} \right]\] & increasing in \[\left[ \frac{\pi }{e},\infty \right]\]

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\[f(x)=\frac{\log (\pi +x)}{\log (e+x)}\] is

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