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1. |
Express force F as a Cartesian vector; then determine its direction angles. |
A. | F = (-2i +j+2k) kN, = 48.2°, = 70.5°, = 48.2° |
B. | F = (-2i +j+2k) kN, = 131.8°, = 70.5°, = 48.2° |
C. | F = (-4i +j+4k) kN, = 48.2°, = 70.5°, = 48.2° |
D. | F = (-4i +2j+4k) kN, = 131.8°, = 70.5°, = 48.2° |
Answer» C. F = (-4i +j+4k) kN, = 48.2¬∞, = 70.5¬∞, = 48.2¬∞ | |