1.

Express force F as a Cartesian vector; then determine its direction angles.

A. F = (-2i +j+2k) kN, = 48.2°, = 70.5°, = 48.2°
B. F = (-2i +j+2k) kN, = 131.8°, = 70.5°, = 48.2°
C. F = (-4i +j+4k) kN, = 48.2°, = 70.5°, = 48.2°
D. F = (-4i +2j+4k) kN, = 131.8°, = 70.5°, = 48.2°
Answer» C. F = (-4i +j+4k) kN, = 48.2¬∞, = 70.5¬∞, = 48.2¬∞


Discussion

No Comment Found

Related MCQs