MCQOPTIONS
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| 1. |
Equation of the tangent to the circle \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\]which is perpendicular to the straight line \[y=mx+c\]is |
| A. | \[y=-\frac{x}{m}\pm a\sqrt{1+{{m}^{2}}}\] |
| B. | \[x+my=\pm \text{ }a\text{ }\sqrt{1+{{m}^{2}}}\] |
| C. | \[x+my=\pm a\sqrt{1+{{(1/m)}^{2}}}\] |
| D. | \[x-my=\pm a\sqrt{1+{{m}^{2}}}\] |
| Answer» C. \[x+my=\pm a\sqrt{1+{{(1/m)}^{2}}}\] | |