MCQOPTIONS
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| 1. |
Equation of motion in the same direction is given by \[{{y}_{1}}=A\sin (\omega t-kx)\], \[{{y}_{2}}=A\sin (\omega t-kx-\theta )\]. The amplitude of the medium particle will be [BHU 2003] |
| A. | \[2A\cos \frac{\theta }{2}\] |
| B. | \[2A\cos \theta \] |
| C. | \[\sqrt{2}A\cos \frac{\theta }{2}\] |
| D. | \[1.2f,\ 1.2\lambda \] |
| Answer» B. \[2A\cos \theta \] | |