1.

Equation of motion in the same direction is given by \[{{y}_{1}}=A\sin (\omega t-kx)\], \[{{y}_{2}}=A\sin (\omega t-kx-\theta )\]. The amplitude of the medium particle will be                         [BHU 2003]

A.            \[2A\cos \frac{\theta }{2}\]   
B.            \[2A\cos \theta \]
C.            \[\sqrt{2}A\cos \frac{\theta }{2}\]                                 
D.            \[1.2f,\ 1.2\lambda \]
Answer» B.            \[2A\cos \theta \]


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