1.

Equation of motion in the same direction are given by                    \[{{y}_{1}}=2a\sin (\omega t-kx)\] and \[{{y}_{2}}=2a\sin (\omega t-kx-\theta )\]            The amplitude of the medium particle will be [CPMT 2004]

A.            \[2a\cos \theta \]              
B.            \[\sqrt{2}a\cos \theta \]
C.            \[4a\cos \theta /2\]          
D.            \[\sqrt{2}a\cos \theta /2\]
Answer» D.            \[\sqrt{2}a\cos \theta /2\]


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