1.

Equation of motion in the same direction are given by \[{{y}_{1}}=2a\sin (\omega t-kx)\] and \[{{y}_{2}}=2a\sin (\omega t-kx-\theta )\] The amplitude of the medium particle will be [CPMT 2004]

A. \[2a\cos \theta \]
B. \[\sqrt{2}a\cos \theta \]
C. \[4a\cos \theta /2\]
D. \[\sqrt{2}a\cos \theta /2\]
Answer» D. \[\sqrt{2}a\cos \theta /2\]


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