MCQOPTIONS
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| 1. |
Equation of motion in the same direction are given by \[{{y}_{1}}=2a\sin (\omega t-kx)\] and \[{{y}_{2}}=2a\sin (\omega t-kx-\theta )\] The amplitude of the medium particle will be [CPMT 2004] |
| A. | \[2a\cos \theta \] |
| B. | \[\sqrt{2}a\cos \theta \] |
| C. | \[4a\cos \theta /2\] |
| D. | \[\sqrt{2}a\cos \theta /2\] |
| Answer» D. \[\sqrt{2}a\cos \theta /2\] | |