1.

Equation of curve through point \[(1,\,0)\]which satisfies the differential equation \[(1+{{y}^{2}})dx-xydy=0\], is            [WB JEE 1986]

A.      \[{{x}^{2}}+{{y}^{2}}=1\]         
B.      \[{{x}^{2}}-{{y}^{2}}=1\]
C.      \[2{{x}^{2}}+{{y}^{2}}=2\]      
D.      None of these
Answer» C.      \[2{{x}^{2}}+{{y}^{2}}=2\]      


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