Equation of angle bisector between the lines \[3x+4y-7=0\] and \[12x+5y+17=0\]are [RPET 1995]

\[\frac{3x+4y+7}{\sqrt{25}}=\frac{12x+5y+17}{\sqrt{169}}\]

\[\frac{3x+4y-7}{\sqrt{25}}=\pm \frac{12x+5y+17}{\sqrt{169}}\]

\[\frac{3x+4y+7}{\sqrt{25}}=\pm \frac{12x+5y+17}{\sqrt{169}}\]

Equation of angle bisector between the lines \[3x+4y-7=0\] and \[12x+5

1.	Equation of angle bisector between the lines \[3x+4y-7=0\] and \[12x+5y+17=0\]are [RPET 1995]
A.	\[\frac{3x+4y-7}{\sqrt{25}}=\pm \frac{12x+5y+17}{\sqrt{169}}\]
B.	\[\frac{3x+4y+7}{\sqrt{25}}=\frac{12x+5y+17}{\sqrt{169}}\]
C.	\[\frac{3x+4y+7}{\sqrt{25}}=\pm \frac{12x+5y+17}{\sqrt{169}}\]
D.	None of these
Answer» B. \[\frac{3x+4y+7}{\sqrt{25}}=\frac{12x+5y+17}{\sqrt{169}}\]

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Equation of angle bisector between the lines \[3x+4y-7=0\] and \[12x+5y+17=0\]are [RPET 1995]

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