Enthalpy of formation of NH‚Äö√á√â is - 46 kJ/kg mole. The e – McqOptions

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1.	Enthalpy of formation of NH‚Äö√á√â is - 46 kJ/kg mole. The enthalpy change for the gaseous reaction, 2NH‚Äö√á√â ‚Äö√ú√≠ N‚Äö√á√á + 3H‚Äö√á√á, is equal to __________ kJ/kg. mole.#
A.	46
B.	92
C.	-23
D.	-92
Answer» C. -23

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