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Electrode potential data are given below. \[F{{e}^{3+}}~\left( aq \right)\text{+}{{\text{e}}^{-}}\to F{{e}^{2+}}\left( aq \right);\]    \[E{}^\circ =+\,0.77\] \[A{{l}^{3+}}\left( aq \right)\text{+3}{{\text{e}}^{-}}\to \text{Al(s);}\]         \[E{}^\circ \text{ }=-\,1.66\text{ }V\] \[B{{r}_{2}}(aq)+2{{e}^{-}}\to 2B{{r}^{-}}(aq);\]    \[E{}^\circ =+\,1.08V\] Based on the data given above, reducing power of \[F{{e}^{2+}}\], Al and \[B{{r}^{-}}\] will increase in the order

A. \[B{{r}^{-}}<F{{e}^{2+}}<Al\]
B. \[F{{e}^{2+}}<Al<B{{r}^{-}}\]
C. \[Al<B{{r}^{-}}<F{{e}^{2+}}\]
D. \[Al<F{{e}^{2+}}<B{{r}^{-}}\]
Answer» B. \[F{{e}^{2+}}<Al<B{{r}^{-}}\]


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