Each atom of an iron bar \[(5\,cm\times 1\,cm\times 1\,cm)\] has a magnetic moment \[1.8\times {{10}^{-23}}\,A{{m}^{2}}.\] Knowing that the density of iron is \[7.78\times {{10}^{3}}\,k{{g}^{-3}}m,\] atomic weight is 56 and Avogadro's number is \[6.02\times {{10}^{23}}\] the magnetic moment of bar in the state of magnetic saturation will be

• A.            \[4.75\,\,A{{m}^{2}}\]      
• B.            \[5.74\,\,A{{m}^{2}}\]
• C.            \[7.54\,\,A{{m}^{2}}\]      
• D.            \[75.4\,\,A{{m}^{2}}\]