MCQOPTIONS
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| 1. |
Due to 10 ampere of current flowing in a circular coil of 10 cm radius, the magnetic field produced at its centre is \[3.14\times {{10}^{-3}}\,Weber/{{m}^{2}}\]. The number of turns in the coil will be [MP PET 1996] |
| A. | 5000 |
| B. | 100 |
| C. | 50 |
| D. | 25 |
| Answer» D. 25 | |