MCQOPTIONS
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| 1. |
Distance of the point \[({{x}_{1}},{{y}_{1}},{{z}_{1}})\] from the line\[\frac{x-{{x}_{2}}}{l}=\frac{y-{{y}_{2}}}{m}=\frac{z-{{z}_{2}}}{n}\], where \[l,\]m and n are the direction cosines of line is |
| A. | \[\sqrt{{{({{x}_{1}}-{{x}_{2}})}^{2}}+{{({{y}_{1}}-{{y}_{2}})}^{2}}+{{({{z}_{1}}-{{z}_{2}})}^{2}}-{{[l({{x}_{1}}-{{x}_{2}})+m({{y}_{1}}-{{y}_{2}})+n({{z}_{1}}-{{z}_{2}})]}^{2}}}\] |
| B. | \[\sqrt{{{({{x}_{2}}-{{x}_{1}})}^{2}}+{{({{y}_{2}}-{{y}_{1}})}^{2}}+{{({{z}_{2}}-{{z}_{1}})}^{2}}}\] |
| C. | \[\sqrt{({{x}_{2}}-{{x}_{1}})l+({{y}_{2}}-{{y}_{1}})m+({{z}_{2}}-{{z}_{1}})n}\] |
| D. | None of these |
| Answer» B. \[\sqrt{{{({{x}_{2}}-{{x}_{1}})}^{2}}+{{({{y}_{2}}-{{y}_{1}})}^{2}}+{{({{z}_{2}}-{{z}_{1}})}^{2}}}\] | |