1.

Direction: A particle initially (i.e., at time \[t=0\]) moving with a velocity u subjected to a retarding force, as a result of which it decelerates at a rate \[a=-k\,\sqrt{v}\] where v is the instantaneous velocity and k is a positive constant.The particle comes to rest in a time

A. \[\frac{2\sqrt{u}}{k}\]
B. \[\frac{\sqrt{u}}{k}\]
C. \[2k\sqrt{u}\]
D. \[k\sqrt{u}\]
Answer» B. \[\frac{\sqrt{u}}{k}\]


Discussion

No Comment Found

Related MCQs