MCQOPTIONS
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| 1. |
Direction: A particle initially (i.e., at time \[t=0\]) moving with a velocity u subjected to a retarding force, as a result of which it decelerates at a rate \[a=-k\,\sqrt{v}\] where v is the instantaneous velocity and k is a positive constant.The particle comes to rest in a time |
| A. | \[\frac{2\sqrt{u}}{k}\] |
| B. | \[\frac{\sqrt{u}}{k}\] |
| C. | \[2k\sqrt{u}\] |
| D. | \[k\sqrt{u}\] |
| Answer» B. \[\frac{\sqrt{u}}{k}\] | |