Diffusor increases the pressure of a fluid at the expense of its:

1.	Diffusor increases the pressure of a fluid at the expense of its:
A.	kinetic energy
B.	impact energy
C.	potential energy
D.	rotational energy
Answer» B. impact energy

Discussion

No Comment Found

Related MCQs

What reaction takes place during photosynthesis?
Which among this is not an exothermic reaction?
SI unit of enthalpy is_______
At constant pressure P the volume of a gas increases from V1 to V2 when ‘Q’ amount of heat is removed from the system. What will happen to internal energy?
In the given system, 20J of heat is supplied to the gas molecules. The spring is initially not elongated or compressed. If the spring gets compressed by 1cm. Calculate the change in internal energy of the system. Spring constant = 200N/m. Assume piston moves slowly.
In the process A to B to C, 20J of heat is supplied from A to B. 20.5J of heat has been removed from B to C and 2J of heat has been added from C to A. Calculate the value of ‘v’ from the given conditions in the diagram. The values of pressure and volume given in the graph are in S.I. units.
A disc spinning with 24J of kinetic energy is kept in a container containing a fluid having a heat capacity of 2000J/K. When the disc comes to rest what will be the change in internal energy if ΔU = 3.5ΔT.
Consider a gas contained in a rigid container of volume 20m3. What will be the change in internal energy if 50J of heat is provided to it? Assume the gas exerts a pressure of 1atm on the walls.
A block of mass 1kg is given a velocity of 5m/s on a horizontal flat surface. What will be the change in internal energy of the block-surface system, when the block comes to rest. The coefficient of kinetic friction is 0.3 and coefficient of static friction is 0.4.
What is the relation between the internal energy and heat supplied in the process 1 & 2 shown in the diagram? Both paths start at A and end at B.

Diffusor increases the pressure of a fluid at the expense of its:

Discussion

No Comment Found

Related MCQs

Reply to Comment