MCQOPTIONS
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| 1. |
Differential equation of \[y=\sec ({{\tan }^{-1}}x)\] is [UPSEAT 2002] |
| A. | \[(1+{{x}^{2}})\frac{dy}{dx}=y+x\] |
| B. | \[(1+{{x}^{2}})\frac{dy}{dx}=y-x\] |
| C. | \[(1+{{x}^{2}})\frac{dy}{dx}=xy\] |
| D. | \[(1+{{x}^{2}})\frac{dy}{dx}=\frac{x}{y}\] |
| Answer» D. \[(1+{{x}^{2}})\frac{dy}{dx}=\frac{x}{y}\] | |