Differential coefficient of \[{{\tan }^{-1}}\sqrt{\frac{1-{{x}^{2}}}{1+{{x}^{2}}}}\] w.r.t. \[{{\cos }^{-1}}({{x}^{2}})\] is [RPET 1996]

Differential coefficient of \[{{\tan }^{-1}}\sqrt{\frac{1-{{x}^{2}}}{1

1.	Differential coefficient of \[{{\tan }^{-1}}\sqrt{\frac{1-{{x}^{2}}}{1+{{x}^{2}}}}\] w.r.t. \[{{\cos }^{-1}}({{x}^{2}})\] is [RPET 1996]
A.	\[\frac{1}{2}\]
B.	\[-\frac{1}{2}\]
C.	1
D.	0
Answer» B. \[-\frac{1}{2}\]

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Differential coefficient of \[{{\tan }^{-1}}\sqrt{\frac{1-{{x}^{2}}}{1+{{x}^{2}}}}\] w.r.t. \[{{\cos }^{-1}}({{x}^{2}})\] is [RPET 1996]

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