Determine the inverse z-transform of: \(X\left( z \right) = \frac{1}{{1 - 1.5{z^{ - 1}} + 0.5{z^{ - 2}}}}\) Where ROC: |Z| > 1

\(x\left[ n \right] = \left\{ {1,\frac{2}{3},\frac{7}{4}, \ldots } \right\}\)

\(x\left[ n \right] = \left\{ {1,\frac{2}{{\begin{array}{*{20}{c}} 3\\ \uparrow \end{array}}},\frac{7}{4}, \ldots } \right\}\)

\(x\left[ n \right] = \left\{ {1,\frac{2}{{\begin{array}{*{20}{c}} 3\\ \uparrow \end{array}}}, - \frac{7}{4}, \ldots } \right\}\)

\(x\left[ n \right] = \left\{ {\begin{array}{*{20}{c}} 1\\ \uparrow \end{array},\frac{3}{2},\frac{7}{4}, \ldots } \right\}\)

Determine the inverse z-transform of: \(X\left( z \right) = \frac{1}{{

1.	Determine the inverse z-transform of: \(X\left( z \right) = \frac{1}{{1 - 1.5{z^{ - 1}} + 0.5{z^{ - 2}}}}\) Where ROC: \|Z\| > 1
A.	\(x\left[ n \right] = \left\{ {1,\frac{2}{3},\frac{7}{4}, \ldots } \right\}\)
B.	\(x\left[ n \right] = \left\{ {1,\frac{2}{{\begin{array}{*{20}{c}} 3\\ \uparrow \end{array}}},\frac{7}{4}, \ldots } \right\}\)
C.	\(x\left[ n \right] = \left\{ {1,\frac{2}{{\begin{array}{*{20}{c}} 3\\ \uparrow \end{array}}}, - \frac{7}{4}, \ldots } \right\}\)
D.	\(x\left[ n \right] = \left\{ {\begin{array}{*{20}{c}} 1\\ \uparrow \end{array},\frac{3}{2},\frac{7}{4}, \ldots } \right\}\)
Answer» E.