1.

Cutoff frequency fC for TEM mode of propagation is:

A. Fc= (2n-1)c/4d√εr -1
B. Fc= (2n-c)/2d(√εr-1)
C. /2d(√εr-1)c) Fc= (2n-1)/4d(√εr)
D. Fc= (2n-1)/8d√εr – 1
Answer» B. Fc= (2n-c)/2d(√εr-1)


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