1.

\[{{\cot }^{-1}}[{{(\cos \alpha )}^{1/2}}]-{{\tan }^{-1}}[{{(\cos \alpha )}^{1/2}}]=x,\]then \[\sin x=\] [AIEEE 2002]

A. \[{{\tan }^{2}}\left( \frac{\alpha }{2} \right)\]
B. \[{{\cot }^{2}}\left( \frac{\alpha }{2} \right)\]
C. \[\tan \alpha \]
D. \[\cot \left( \frac{\alpha }{2} \right)\]
Answer» B. \[{{\cot }^{2}}\left( \frac{\alpha }{2} \right)\]


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