\[{{\cos }^{2}}\left( \frac{\pi }{4}-\beta \right)-{{\sin }^{2}}\left( \alpha -\frac{\pi }{4} \right)=\]

\[\sin (\alpha +\beta )\sin (\alpha -\beta )\]

\[\cos (\alpha +\beta )\cos (\alpha -\beta )\]

\[\sin (\alpha -\beta )\cos (\alpha +\beta )\]

\[\sin (\alpha +\beta )\cos (\alpha -\beta )\]

\[{{\cos }^{2}}\left( \frac{\pi }{4}-\beta \right)-{{\sin }^{2}}\left(

1.	\[{{\cos }^{2}}\left( \frac{\pi }{4}-\beta \right)-{{\sin }^{2}}\left( \alpha -\frac{\pi }{4} \right)=\]
A.	\[\sin (\alpha +\beta )\sin (\alpha -\beta )\]
B.	\[\cos (\alpha +\beta )\cos (\alpha -\beta )\]
C.	\[\sin (\alpha -\beta )\cos (\alpha +\beta )\]
D.	\[\sin (\alpha +\beta )\cos (\alpha -\beta )\]
Answer» E.

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\[{{\cos }^{2}}\left( \frac{\pi }{4}-\beta \right)-{{\sin }^{2}}\left( \alpha -\frac{\pi }{4} \right)=\]

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