\[{{\cos }^{2}}\alpha +{{\cos }^{2}}(\alpha +120{}^\circ )+{{\cos }^{2}}(\alpha -120{}^\circ )\] is equal to [MP PET 1993]

\[{{\cos }^{2}}\alpha +{{\cos }^{2}}(\alpha +120{}^\circ )+{{\cos }^{2

1.	\[{{\cos }^{2}}\alpha +{{\cos }^{2}}(\alpha +120{}^\circ )+{{\cos }^{2}}(\alpha -120{}^\circ )\] is equal to [MP PET 1993]
A.	3/2
B.	1
C.	1/2
D.	0
Answer» B. 1

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\[{{\cos }^{2}}\alpha +{{\cos }^{2}}(\alpha +120{}^\circ )+{{\cos }^{2}}(\alpha -120{}^\circ )\] is equal to [MP PET 1993]

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