Consider the function \(F(s) = \frac{5}{{s({s^2} + 3s + 2)}}\), where F(s) is Laplace transform of function f(t). The initial value of f(t) is:

Consider the function \(F(s) = \frac{5}{{s({s^2} + 3s + 2)}}\), where

1.	Consider the function \(F(s) = \frac{5}{{s({s^2} + 3s + 2)}}\), where F(s) is Laplace transform of function f(t). The initial value of f(t) is:
A.	5
B.	5/2
C.	5/3
D.	0
Answer» E.