1.

Consider an electromagnetic wave propagating in vacuum. Choose the correct statement:                  

A. For an electromagnetic wave propagating in \[+y\] direction the electric field is \[\vec{E}=\frac{1}{\sqrt{2}}{{E}_{yz}}\,(x,t)\,\hat{z}\] and the magnetic field is \[\overrightarrow{B}=\frac{1}{\sqrt{2}}{{B}_{z}}(x,t)\hat{y}\]
B. For an electromagnetic wave propagating in \[+y\] direction the electric field is \[\vec{E}=\frac{1}{\sqrt{2}}{{E}_{yz}}(x,t)\,\hat{z}\] and the magnetic field is \[\vec{B}=\frac{1}{\sqrt{2}}{{B}_{yz}}(x,t)\,\hat{y}\]
C. For an electromagnetic wave propagating in \[+x\] direction the electric field is \[\vec{E}=\frac{1}{\sqrt{2}}{{E}_{yz}}\,(y,\,\,z,\,\,t)\]  \[\left( \hat{y}+\hat{z} \right)\] and the magnetic field is \[\vec{B}=\frac{1}{\sqrt{2}}{{B}_{yz}}\,(y,\,\,z,\,\,t)\,(\hat{y}+\hat{z})\]
D. For an electromagnetic wave propagating in \[+x\] direction the electric field is \[\vec{E}=\frac{1}{\sqrt{2}}{{E}_{yz}}\,(x,t)\,\left( \hat{y}-\hat{z} \right)\]and the magnetic field is \[\vec{B}=\frac{1}{\sqrt{2}}{{B}_{yz}}\,(x,t)\,\left( \hat{y}+\hat{z} \right)\]
Answer» E.


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