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				| 1. | Consider a wide rigid-boundary canal with bed slope of 0.004, Manning’s n = 0.18, and depth of flow = 0.88 m. The average boundary shear stress will be | 
| A. | 17.2 × 106 N / mm2 | 
| B. | 18.2 × 106 N / mm2 | 
| C. | 19.2 × 106 N / mm2 | 
| D. | 34.5 × 106 N / mm2 | 
| Answer» E. | |