 
			 
			MCQOPTIONS
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				| 1. | Consider a signal \(x\left[ n \right] = {\left( {\frac{1}{2}} \right)^n}1\left[ n \right]\), where 1[n] = 0 if n < 0, and 1[n] = 1 if n ≥ 0. The z-transform of x[n - k], k > 0 is \(\frac{{{z^{ - k}}}}{{1 - \frac{1}{2}\;{z^{ - 1}}}}\) with region of convergence being | 
| A. | |z| < 2 | 
| B. | |z| > 2 | 
| C. | |z| < 1/2 | 
| D. | |z| > 1/2 | 
| Answer» E. | |