MCQOPTIONS
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| 1. |
Consider a signal defined by\(x\left( t \right) = \left\{ {\begin{array}{*{20}{c}} {{e^{~j10t}}}&{for\left| t \right| \le 1}\\ 0&{for\left| t \right| > 1} \end{array}} \right.\)Its Fourier Transform is |
| A. | \(\frac{{2\sin \left( {\omega - 10} \right)}}{{\omega - 10}}\) |
| B. | \(\frac{{2{e^{j10}}\sin \left( {\omega - 10} \right)}}{{\omega - 10}}\) |
| C. | \(\frac{{2sin\omega }}{{\omega - 10}}\) |
| D. | \(\frac{{{e^{j10\omega }}2sin\omega }}{\omega }\) |
| Answer» B. \(\frac{{2{e^{j10}}\sin \left( {\omega - 10} \right)}}{{\omega - 10}}\) | |