MCQOPTIONS
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| 1. |
Consider 3rd orbit of \[H{{e}^{+}}\](Helium), using non-relativistic approach, the speed of electron in this orbit will be [given \[K=9\times {{10}^{9}}\]constant and h (Plank's Constant) \[6.6\times {{10}^{-34}}Js\]] |
| A. | \[1.46\times {{10}^{6}}m/s\] |
| B. | \[0.73\times {{10}^{6}}m/s\] |
| C. | \[3.0\times {{10}^{8}}m/s\] |
| D. | \[2.92\times {{10}^{6}}m/s\] |
| Answer» B. \[0.73\times {{10}^{6}}m/s\] | |