Compound 'A' (molecular formula $${{C}_{3}}{{H}_{8}}O$$) is treated with acidified potassium dichromate to form a product 'B' (molecular formula $${{C}_{3}}{{H}_{6}}O$$). 'B' forms a shining silver mirror on warming with ammonical silver nitrate. 'B' when treated with an aqueous solution of $${{H}_{2}}NCONHN{{H}_{2}}.HCl$$ and sodium acetate gives a product 'C'. Identify the structure of 'C'?

Question

TuteeHUB · Accepted Answer

$$C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,=NNHCON{{H}_{2}}$$

TuteeHUB · Answer

$$C{{H}_{3}}C{{H}_{2}}CH=NNHCON{{H}_{2}}$$

TuteeHUB · Answer

$$C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,=NCONHN{{H}_{2}}$$

TuteeHUB · Answer

$$C{{H}_{3}}C{{H}_{2}}CH=NCONHN{{H}_{2}}$$

1.	Compound 'A' (molecular formula \[{{C}_{3}}{{H}_{8}}O\]) is treated with acidified potassium dichromate to form a product 'B' (molecular formula \[{{C}_{3}}{{H}_{6}}O\]). 'B' forms a shining silver mirror on warming with ammonical silver nitrate. 'B' when treated with an aqueous solution of \[{{H}_{2}}NCONHN{{H}_{2}}.HCl\] and sodium acetate gives a product 'C'. Identify the structure of 'C'?
A.	\[C{{H}_{3}}C{{H}_{2}}CH=NNHCON{{H}_{2}}\]
B.	\[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{\|}{\mathop{C}}\,}}\,=NNHCON{{H}_{2}}\]
C.	\[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{\|}{\mathop{C}}\,}}\,=NCONHN{{H}_{2}}\]
D.	\[C{{H}_{3}}C{{H}_{2}}CH=NCONHN{{H}_{2}}\]
Answer» B. \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{\|}{\mathop{C}}\,}}\,=NNHCON{{H}_{2}}\]

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