Comment on the output of the following C code.#include <stdio.h> int main() { int k; for (k = 0; k < 10; k++) int m = k; printf("%d", m); }

m is out of scope when printf is called

Redeclaration of m in same scope throws error

Syntax error in declaration of m

No errors, program will show the output 15

Comment on the output of the following C code.#include <stdio.h> int m

1.	Comment on the output of the following C code. #include <stdio.h> int main() { int k; for (k = 0; k < 10; k++) int m = k; printf("%d", m); }
A.	Redeclaration of m in same scope throws error
B.	Syntax error in declaration of m
C.	m is out of scope when printf is called
D.	No errors, program will show the output 15
E.	None of these
Answer» C. m is out of scope when printf is called

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Comment on the output of the following C code.#include <stdio.h> int main() { int k; for (k = 0; k < 10; k++) int m = k; printf("%d", m); }

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Comment on the output of the following C code.
#include <stdio.h>
int main()
{
int k;
for (k = 0; k < 10; k++)
int m = k;
printf("%d", m);
}