Colebrook equation for friction factor in turbulent flow is given by, – McqOptions

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1.	Colebrook equation for friction factor in turbulent flow is given by, f-0.5 = -4 loge [(ε/D) + (1.26/NRe √F). It reduces to Nikuradse equation for a value of (ϵ/D) equal to __________________?
A.	0
B.	1
C.	∞
D.	0.5
Answer» C. ∞

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