Circles \[{{(x+a)}^{2}}+{{(y+b)}^{2}}={{a}^{2}}\] and \[{{(x+\alpha )}^{2}}\] \[+{{(y+\beta )}^{2}}=\]\[{{\beta }^{2}}\] cut orthogonally, if

\[a\alpha +b\beta ={{a}^{2}}+{{b}^{2}}\]

\[a\alpha +b\beta ={{b}^{2}}+{{\alpha }^{2}}\]

\[2(a\alpha +b\beta )={{b}^{2}}+{{\alpha }^{2}}\]

Circles \[{{(x+a)}^{2}}+{{(y+b)}^{2}}={{a}^{2}}\] and \[{{(x+\alpha )}

1.	Circles \[{{(x+a)}^{2}}+{{(y+b)}^{2}}={{a}^{2}}\] and \[{{(x+\alpha )}^{2}}\] \[+{{(y+\beta )}^{2}}=\]\[{{\beta }^{2}}\] cut orthogonally, if
A.	\[a\alpha +b\beta ={{b}^{2}}+{{\alpha }^{2}}\]
B.	\[2(a\alpha +b\beta )={{b}^{2}}+{{\alpha }^{2}}\]
C.	\[a\alpha +b\beta ={{a}^{2}}+{{b}^{2}}\]
D.	None of these
Answer» C. \[a\alpha +b\beta ={{a}^{2}}+{{b}^{2}}\]

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Circles \[{{(x+a)}^{2}}+{{(y+b)}^{2}}={{a}^{2}}\] and \[{{(x+\alpha )}^{2}}\] \[+{{(y+\beta )}^{2}}=\]\[{{\beta }^{2}}\] cut orthogonally, if

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