\[CH\equiv CH\underset{{{H}_{2}}S{{O}_{4}}}{\mathop{\xrightarrow{HgS{{O}_{4}}}}}\,\underset{{{H}_{2}}O}{\mathop{\xrightarrow{C{{H}_{3}}MgBr}}}\,\xrightarrow{P/B{{r}_{2}}}\] [DPMT 2005]

\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\]

\[CH\equiv CH\underset{{{H}_{2}}S{{O}_{4}}}{\mathop{\xrightarrow{HgS{{

1.	\[CH\equiv CH\underset{{{H}_{2}}S{{O}_{4}}}{\mathop{\xrightarrow{HgS{{O}_{4}}}}}\,\underset{{{H}_{2}}O}{\mathop{\xrightarrow{C{{H}_{3}}MgBr}}}\,\xrightarrow{P/B{{r}_{2}}}\] [DPMT 2005]
A.	\[C{{H}_{3}}CH(Br)C{{H}_{3}}\]
B.	\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\]
C.	\[C{{H}_{2}}=CH-Br\]
D.	\[BrCH=CH-C{{H}_{3}}\]
Answer» B. \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\]

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\[CH\equiv CH\underset{{{H}_{2}}S{{O}_{4}}}{\mathop{\xrightarrow{HgS{{O}_{4}}}}}\,\underset{{{H}_{2}}O}{\mathop{\xrightarrow{C{{H}_{3}}MgBr}}}\,\xrightarrow{P/B{{r}_{2}}}\] [DPMT 2005]

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